Verbindungsaufgaben 1
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8a – (4a + 7) · 3 + 10 =
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(5x – 2y) · 4 – (3x – 2y) =
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(4u² – 5u + 1) · 3u + 5 · (3u² – u) =
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2 · [5e – (4e + 7) + 4] =
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3a · (2a + 3b) – (a + b) · 6a =
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(6r – 8) · (6r + 8) + 65 – 12r² =
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10c – (c² + 25) + (c – 5)² =
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(x + 5)² – (10x + 25) =
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(2g – h) · (3g – h) + 5h · (g – h) =
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9a² + 6ab – (3a + b)² =
Last modified: Monday, 1 December 2014, 7:16 AM